If the 4th and 9th terms of a G.P. be 54 and 13122 respectively, find the G.P.

Explanation

Let a be the first term and r be the common ratio of the given GP.


Then,
`T_4=54⇒ar^(4−1)=54⇒ar^3=54 . . .. (i)`


And,
`T_9=13122⇒ar^(9−1)=13122``=>ar^8=13122 . . .(ii)`


On dividing (ii) by (i), we get


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