If the first and the nth terms of a G.P., are `aa n db ,` respectively, and if `P` is hte product of the first `n` terms prove that `P^2=(a b)^ndot`

Explanation

1st term =a

nth term =b

P= product of n terms



`G.P.=a,ar,ar^2.....ar^(n−1)`


`→b=ar^(n−1)`
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