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Find the 4th term from the end of the G.P. `2/(27),2/9,2/3, ,, , , , ,162.`

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Here, first term, `a=2/27`
Common ratio, r = `(a_2)/(a_1)`=`(2/9)/(2/27)`=3
Last term, l = 162
After reversing the given G.P., we get another G.P. whose first term is l and common ratio is `1/r`.
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RD SHARMA-GEOMETRIC PROGRESSIONS-Solved Examples And Exercises
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  2. Find: the 10th term of the G.P. sqrt(2),1/(sqrt(2)),1/(2sqrt(2)),

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  3. Find the 4th term from the end of the G.P. 2/(27),2/9,2/3, ,, , , ,...

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  4. Which term of the progression 0.004,0.02,0.1,… is 12.5.?

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  7. Which term of the G.P.: \ sqrt(3),3,3sqrt(3), i s\ 729 ?

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  8. Which term of the G.P.: 1/3,1/9,1/(27) i s1/(19683)?

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  10. The fourth term of a G.P. is 27 and the 7th term is 729, find the G....

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  12. If the G.Ps 5 , 10, 20, and 1280, 640, 320 have their nth terms equ...

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  14. The 4th term of a G.P. is square of its second term and the first t...

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  15. In a GP the 3rd term is 24 and the 6th term is 192. Find the 10th t...

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  16. If a ,\ b ,\ c ,\ d\ a n d\ p are different real numbers such that: (a...

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  17. If (a+b x)/(a-b x)=(b+c x)/(b-c x)=(c+dx)/(c-dx)(x!=0) , then show tha...

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  19. Find three numbers in G.P. whose sum is 65 and whose product is 3375.

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