Which term of the G.P.: `1/3,1/9,1/(27) i s1/(19683)?`

Explanation

To find which term of the geometric progression (G.P.) \( \frac{1}{3}, \frac{1}{9}, \frac{1}{27}, \ldots \) is equal to \( \frac{1}{19683} \), we can follow these steps:

### Step 1: Identify the first term and the common ratio
The first term \( a \) of the G.P. is:
\[ a = \frac{1}{3} \]
To find the common ratio \( r \), we can divide the second term by the first term:
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