The sum of first three terms of a G.P is 16 and the sum of the next three terms is 128. Determine the first term, the common ratio and the sum to n terms of the G.P.

Explanation

Let a be the first term and r the common ratio of the G.P.


`a+ar+ar^2=16`


and, `ar^3+ar^4+ar^5=128`


`a(1+r+r^2)=16`
and, `ar^3(1+r+r^2)=128`


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