Find the sum of the following geometric progression: `(a^2-b^2),\ (a-b),\ ((a-b)/(a+b)),\ to\ n` terms.

Explanation

Given series is,
`(a^2−b^2),(a−b),(a+ba−b​),........... `


Here, First term `=(a^2−b^2)` and` r=1/(a+b)`
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`S_n​=(a(1−r^n))/(1-r)`
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=`((a^2−b^2)(1−1/(a+b)^n​))/(​1-1/(a+b))`

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