Find the sum of the following geometric progression: `4,2,1,1//2, ..... 10 ` terms.

Explanation

It is given that the first term of G.P is `a_1​=1` and the second term is `a_2​=2`, therefore,


`r​=2`


In the given geometric series, the first term is `a=1`, the common ratio is` r=2` and the number of terms are` n=10`, therefore,


`S_10​=(1(2^10−1))/(2-1)​=1024−1​=1023`