Find the sum of the series upto infinite terms `3/4-5/4^2+3/4^3-5/4^4+...`

Explanation

Given, `3/4-5/4^2+3/4^3-5/4^4+...`

=`3(1/4+1/4^3+...........)-5(1/4^2+1/4^4+........)`

=`3((1/4)/(1-(1/16)))-5((1/16)/(1-1/16))`

=`3(4/15)-5(1/15)`

=`12/15-5/15`

=`7/15`