Insert `6` geometric means between `27` and `1/(81)`

Explanation

Let,


`G_1, G_2, G_3, G_4, G_5, G_6` be `6` are GM


Then, `27, G_1, G_2, G_3, G_4, G_5, G_6, 1/81` are in G.P.


`a=27, b=1/81`


`n=6`


`r=(b/a)^((1)/(n+1))`


`r=(((1)/(81))/27)^(1/(6+1))`


`r=(1/2187)^(1/(7))`


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