If `S` be the sum `P` the product and `R` be the sum of the reciprocals of `n` terms of a GP then `p^2` is equal to
(a).`S//R`
(b). `R//S`
(c). `(R//S)^n`
(d). `(S//R)^n`

Explanation

`S=a+ar+ar^2+ar^3+ar^4.....+ar^(r-1)` n-terms


`S=(a(1-r^n))/(1-r)`


`P=a.a.ar^2...ar^(r-1)`


`=> a^nr^(1+2+3+...)=a^rr^(n-1)`


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