The base of an equilateral triangle with side `2a` lies along the y-axis such that the mid point of the base is at the origin. Find the vertices of the triangle.

Explanation

Suppose a equilateral triangle `triangleABC` and
let `BC` be the base of it.

We have given that base of it i.e. `BC = 2a` and mid-point of `BC` is at the
origin.

Hence, coordinates of `B` and `C` are `(0,a)` and `(0,−a)` respectively.

As the triangle `ABC` is equilateral.

Vertex A lies on x-axis as the `DeltaABC` is equilateral .
Now let its coordinates be `(x,0)`.
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