Find the point to which the origin should be shifted so that the equation `y^2-6y-4x+13=0` is transferred to the form `y^2+Ax=0`

Explanation

`y^2+Ax=0`

`y^2 − 6 y + ( 3 2 − 3 2 ) − 4 x + 13 = 0`

`(y-3)2+4-4x=0`

`(y-3)2+4(1-x)=0`

`(y-3)^2-4(x-1)=0`
`y^2+Ax=0`

`A=-4`.

`y − 3 = 0`

`y = 3`
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