Find the equation of the circle with: Center `(a\ cosalpha,\ a\ sinalpha)` and radius `adot`

Explanation

Here, `h=a cos alpha, k=a cos alpha`

`a cos alpha` and radius `=a`

`therefore` Required equation:

`(x-a cos alpha)^{2}+(y-a sin alpha)^{2}=(a)^{2}`


`Rightarrow x^{2}+a^{2} cos ^{2} alpha-2 a x cos alpha+y^{2}+a^{2} sin ^{2} alpha-2 a y sin alpha=a^{2} `

`Rightarrow x^{2}+a^{2}(sin ^{2} alpha+cos ^{2} alpha)-2 a x cos alpha+y^{2}-2 a y sin alpha=a^{2} `

`Rightarrow x^{2}+a^{2}-2 a x cos alpha+y^{2}-2 a y sin alpha=a^{2} `

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