A circle whose centre is the point of intersection of the lines `2x-3y+4=0\ a n d\ 3x+4y-5=0` passes through the origin. Find its equation.

Explanation

To find the equation of the circle whose center is the point of intersection of the lines \(2x - 3y + 4 = 0\) and \(3x + 4y - 5 = 0\) and which passes through the origin, we can follow these steps:

### Step 1: Find the point of intersection of the two lines.
We have the equations:
1. \(2x - 3y + 4 = 0\) (Equation 1)
2. \(3x + 4y - 5 = 0\) (Equation 2)

To find the intersection, we can solve these equations simultaneously.
...