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If the lines 3x-4y-7 = 0 and 2x-3y-5=0 a...

If the lines `3x-4y-7 = `0 and `2x-3y-5=0` are two diameters of a circle of area `49pi` square units, the equation of the circle is:

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Given Equations of diameter :`3 x-4 y-7=0 ldots ldots (1) `

`2 x-3 y-5=0 ldots ldots (2)`

Solving equations

`3 x-4 y-7=0 quad times 2 `

`2 x-3 y-5=0 times 3 `

`6 x-8 y-14=0 ldots (3) `

`6 x-9 y-15=0 ldots (4)`

Subtract equation (3) from (4),

...
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