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Find the coordinates of the centre and radius of each of the following circle: `x^2+y^2+6x-8y-24=0`

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Given the equation of the circle is `x^2+y^2-6x-8y+24=0`
or `(x^2-6x+9)+(y^2-8x+16)-1=0`
or `(x-3)^3+(y-4)^2=1`
So, the centre is `(3,4)` and radius is `1`
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