Find the equation of the circle which passes through the points (3, -2), `(-2, 0)` and has its centre on the line `2x - y =3.`

Options

A. `142`
B. `130`
C. `125`
D. `145`

Answer

`145`

Explanation

Equation of circle with centre `(h, k)` is

`(x-h)^2+(y-k)^2=r^2`

the circle passes through `(3,-2)`

put the values we got,

`(3-h)^2+(-2-k)^2=r^2 `

=>` 9+h^2-6 h+4+k^2+4 k=r^2 `

=>` h^2+k^2-6 h+4 k+13=r^2`...... (1)

then the circle passes through `(-2,0)`

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