Find the equation of the circle which circumscribes the triangle formed by the line: `\ x+y+3=0,\ x-y+1=0\ a n d\ x=3`

Options

A. `x^2+y^2-6x+2y-15=0`
B. `3x^2+3y^2+9=10`
C. `x^2+y^2+6x-2y=0`
D. none of the above

Answer

`x^2+y^2-6x+2y-15=0`

Explanation

In triangle,

Let us suppose, `A B` represent the line `x+y+3=0`.

`B C` represent the line `x-y+1=0`.

And `C A` represent the line `x=3`.

Intersection point of `(1)` and `(3)` is `(3,-6)`

Intersection point of `(1)` and `(2)` is `(-2,-1)`.

Intersection point of `(2)` and `(3)` is `(3,4)`.

the coordinates of A, B and C are `(3,-6),(-2,-1)` and `(3,4)`, respectively.

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