Find the equation of the circle which circumscribes the triangle formed by the line: `\ \ x+y=2,\ 3x-4y=6\ a n d\ x-y=0.`

Explanation

Given:


lines `x+y=2`


`3 x-4 y=6 `


`x-y=0`


By solving these lines, we find the intersection points A(2,0), B(-6,-6),


The standard form of the equation of the circle is,


`x^{2}+y^{2}+2 a x+2 b y+c=0`


Put the points (2,0) in equation (1),


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