Find the equation of the circle concentric with the circle `x^2 + y^2 - 4x - 6y - 3 = 0` and which touches the y axis

Explanation

Given `x^2+y^2-4x-6x-3=0`


so centre is `(2,3)`


Now, `(x-3)^2+9y-2)^2=4`


`x^2+4-4x+y^2+9-6y=4`


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