Find the number of integral values of `lambda` for which `x^2+y^2+lambdax+(1-lambda)y+5=0` is the equation of a circle whose radius does not exceed 5.

Explanation

Given: equation of circle is` x^{2}+y^{2}+lambda x+(1-lambda) y+5=0`


Equation for a circle `x^{2}+y^{2}+2 a x+2 b y+c=0`


`Rightarrow Centre =(-a,-b)`


`Rightarrow Radius =sqrt{a^{2}+b^{2}-c}`


the radius of a circle cannot be less than 0 .


Assume ' r ' be the radius of the circle.


`Rightarrow 0 leq r leq 5`


`Rightarrow 0 leq sqrt{(frac{-lambda}{2})^{2}+(frac{lambda-1}{2})^{2}-5} leq 5`


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