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If the centroid of an equilateral triangle is (1,1) and its one vertex is (-1, 2), then the equation of its circumcircle is: is `x^2+y^2-2x-2y-3=0` b. `x^2+y^2+2x-2y-3=0` c. `x^2+y^2+2x+2y-3=0` d. none of these

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Given centroid of an equilateral triangle is {G}(1,1).
We know that in an equilateral triangle, centroid, circumcenter and incenter are at the same point.
So, the circumcenter is at G(1,1).
Given one vertex of equilateral triangle at {A}(-1,2)
So, circumradius ={AG}`=sqrt{5}`
So, equation of circumcircle is
...
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