If `(x ,3)a n d\ (3,5)` are the extremities of a diameter of a circle with centre at `(2, y)` then the values of `x\ a n d\ y` are a. (3,1) b. `x=1, y=4` c. `x=8, y=2` d. none of these

Explanation

We have given `(x ,3)a n d\ (3,5)`
are the extremities of a diameter of a circle with centre at `(2, y)`

Then the center is at the midpoint of the extremities of the diameter can be given as

Midpoint of `(x_1,y_1),(x_2,y_2) `is

`X=(x_1+x_2)/2`and `Y=(y_1+y_2)/2`

Hence,we have

`(x+3)/2=2`
`impliesx=1`
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