Equation of the circle through origin which cuts intercepts of length `a\ a n d\ b` on axes is ^2=a x+b y=0` b. `x^2+y^2-a x-b y=0` c. `x^2+y^2+b x+a y=0` d. none of these

The equation of the circle passing through the origin which cuts of intercept of length 6 and 8 from the axes is x^(2)+y^(2)-12x-16y=0 b.x^(2)+y^(2)+12x+16y=0cx^(2)+y^(2)-3x+4y=2=0 d.none of these

Show that equation of the circle passing through the origin and cutting intercepts a and b on the coordinate axes is x^2 + y^2 - ax - by =0

Find the equation of the circle which passes through the origin and cuts off intercepts a and b respectively from x and y-axes .

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^(2)+y^(2)-6x+8=0 and x^(2)+y^(2)-2x-2y-7=0 is

The equation of the circle touching Y-axis at (0,3) and making intercept of 8 units on the axis (a) x^(2)+y^(2)-10x-6y-9=0 (b) x^(2)+y^(2)-10x-6y+9=0 (c) x^(2)+y^(2)+10x-6y-9=0 (d) x^(2)+y^(2)+10x+6y+9=0

The equation of the circle passing through (1, 0) and (0, 1) and having smallest possible radius is : (A) 2x^2 + y^2 - 2x-y=0 (B) x^2 + 2y^2 - x - 2y = 0 (C) x^2 = y^2 - x - y = 0 (D) x^2 + y^2 + x + y = 0

The equation of the circle through the points of intersection of x y -1 -0, x y -2x-4 y l 0 and touching the line x 2y 0, is (B) x y 2 x+20 (C) x y (D) 2 (x2 y x 2

The equation of a line through (2, -4) which cuts the axes so that the intercepts are equal in magnitude is : (A) x+y+2=0 (B) x-y+2=0 (C) x+y+6=0 (D) x+y-6=0

The equation of the circle and its chord are respectively x^2 + y^2 = a^2 and x + y = a . The equation of circle with this chord as diameter is : (A) x^2 + y^2 + ax + ay + a^2 = 0 (B) x^2 + y^2 + 2ax + 2ay = 0 (C) x^2 + y^2 - ax - ay = 0 (D) ax^2 + ay^2 + x + y = 0