In each of the following find the equations of the hyperbola satisfying he given condition: `foc i\ (0,pm13)` conjugate axis `=24`

Explanation

We have given foci `(0,+-13)` and cojugate axis=24

Hence, 2b=24

Therefore, the equation of the hyperbola is of the form

`y^2/a^2− x^2/b^2=1`

Since the foci are `(0,+-13),c=13`.

We know that
`a^2+b^2=c^2`

`a^2+12^2=13^2`

`b^2=169−144=25`

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