The latus rectum of the hyperbola `16 x^2-9y^2=144` is a.`16//3` b. `32//3` c. `8//3` d. `4//3`

Explanation

standard form of hyperbola `16 x^{2}-9 y^{2}=144` is `\frac{x^{2}}{9}-\frac{y^{2}}{16}=1`.

Here,

`a^{2}=9, b^{2}=16`

Latus rectum of hyperbola `=\frac{2 b^{2}}{a}=\frac{2 \times 16}{3}=\frac{32}{3}`