Find the locus of the point which is equidistant from the points `A(0,2,3)a n d\ (2,-2,1)dot`

Explanation

Let P(x,y,z) be any purpose that is equal from A(0,2,3) and B(2,−2,1).
Then ,`(PA=PB)`
`PA^2=PB^2`
`sqrt((x-0)^2+(y-2)^2+(z-3)^2)=sqrt((x-2)^2+(y+2)^2+(z-1)^2)`
`=>4x−8y−4z+4=0`
`=>x−2y−z+1=0`
Therefore the calculated locus is `x−2y−z+1=0`