Find the equation of the hyperbola whose foci are (8, 3) and (0, 3) and eccentricity is `4/3` .

Explanation

Centre of hyper set`((8+0)/2,(3+3)/2)`

Let 2a and 2b be the length of transverse and conjugate axis of hyperbola.

Let e be the receipt for equation of hyper.

`(x-4)^2/a^2+(y-3)^2/b^2=1`

`S_1S_2=sqrt((b-a)^2+(c-a)^2`

`b^2=a^2(e^2-1)`

`b^2=9(16/9-1)`

`=16-9=7`

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