Determine the point on yz-plane which is equidistant from points `A(2,0,3),\ b(0,3,2)a n d\ C(0,0,1)dot`

Explanation

Since `x`-coordinate of every point in `yz`-plane is zero.


Let `P (0, y, z) `be a point on the yz-plane such that `PA = PB = PC.`


Now `PA = PB`


` (0 – 2)^2 + (y – 0)^2 + (z – 3)^2 = (0 – 0)^2 + (y – 3)^2 + (z – 2)^2`


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