A particle `A` is projected with speed `V_(A)` from a point making an angle `60^(@)` with the horizontal. At the same instant, a second particle `B` is thrown vertically upwards from a point directly below the maximum height point of parabolic path of A, with velocity `V_(B)` . If the two particles collide then the ratio of `V_(A)//V_(B)` should be:

Options

A. `1`
B. `2//sqrt(3)`
C. `sqrt(3)//2`
D. `sqrt(3)`

Answer

B

Explanation

`V_(A) sin 60^(@) =V_(B)`
`rArr (V_(A))/(V_(B))=2/(sqrt(3))`