A gas is found to be obeyed the law p^2V...

A gas is found to be obeyed the law `p^2V = constant`. The initial temperature and volume are `T_0 and V_0`. If the gas expands to a volume `3 V_0`, then the final temperature becomes.

A

`T/(sqrt(3))`

B

3T

C

`T/3`

D

`Tsqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:

D

From equation PV=nRT and `P^(2) V=` constant
`(T^(2))/V`=constant
`T_(2)=sqrt(3)T`

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