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In the figure shown sin i/sin r is equal...

In the figure shown `sin i/sin r` is equal to

A

`(mu_(2)^(2))/(mu_(3)mu_(1))`

B

`(mu_(3))/(mu_(1))`

C

`(mu_(3)mu_(1))/(mu_(2)^(2))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B

`mu_(1)=sin i=mu_(2) sin theta .....(i)`
`mu_(2) sin theta= mu_(3) sin r.....(ii)`
from (i) and (ii)
`mu_(1) sin i=mu_(3) sin r`
`(sin i)/(sin r) =(mu_(3))/(mu_(1))`
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