Consider two rods of same length and different specific heats (`S_1` and `S_2`), conductivities `K_1` and `K_2` and area of cross section (`A_1` and `A_2`) and both having temperature `T_1` and `T_2` at their ends. If the rate of heat loss due to conduction is equal then

Options

A. `K_(1)=K_(2)`
B. `K_(1)S_(1)=K_(2)S_(2)`
C. `(K_(1))/(A_(1)S_(1))=(K_(2))/(A_(2)S_(2))`
D. `K_(1)A_(1)=K_(2)A_(2)`

Answer

D

Explanation

Thermal resistance should be equal, to `l/(K_(1)A_(1))=l/(K_(2)A_(2))rArr K_(1)A_(1) =K_(2)A_(2)`