The number of `alpha` and `beta`- emitted during the radioactive decay chain starting from `._(226)^(88) Ra` and ending at `._(206)^(82) Pb` is

Options

A. `3alpha &6 beta^(-)`
B. `4alpha &5 beta^(-)`
C. `5alpha &4 beta^(-)`
D. `6alpha &6 beta^(-)`

Answer

C

Explanation

`._(226)^(88) Ra+n(._(2)He^(4))+m(._(1)beta^(0))to ._(206)^(82) Pb`
Where n and m are respectively the required number of `alpha` and `beta` particles. Clearly from the options given, only (C)
satisfy the above reactions.