In a photoelectric effect experiment, stopping potential changes by 30 volt if we change frequency of the radiation. Then the magnitude of change in the frequency is : `(h=6xx10^(-34) J-s)`

Options

A. `4xx10^(-15) s^(-1)`
B. `8xx10^(15) s^(-1)`
C. `10^(10) s^(-1)`
D. `18xx10^(15) s^(-1)`

Answer

B

Explanation

`eV_(0) =h upsilon-h upsilon_(0)`
`V_(0)=(h/e)upsilon-(h/e) upsilon_(0)`
Slope `m=h/e =(DeltaV_(0))/(Deltaupsilon)`
`Deltaupsilon=e/hxxDeltaV_(0)`
`=(1.6xx10^(-10))/(6xx10^(-34)) xx30 =8xx10^(15) s^(-1)`