the photon radiated from hydrogen corresponding to the second line of Lyman series is absorbed by a hydrogen like atom X in the second excited state. Then, the hydrogen-like atom X makes a transition of nth orbit.

Options

A. `X=He^(+), n=4`
B. `X=Li^(++), n=6`
C. `X=He^(+),n=6`
D. `X=Li^(++) , n=9`

Answer

D

Explanation

(D) Energy of `n^(th)` sate in hydrogen is same as energy of `3n^(th)` state in `Li^(++)` `:. 3 to 1` transition in H would give same energy as the `3xx to 1xx3` transition in `Li^(++)`.