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What percentage increase in wavelength l...

What percentage increase in wavelength leads to `75%` loss of photon energy in a photon-electron collision?

A

200

B

100

C

67

D

300

Text Solution

Verified by Experts

The correct Answer is:
D
Energy of a photons =`(hC)/(lambda)=E, E =0.25 E =(hC)/(lambda)`
So % change in wavelength `=(4lambda-lambda)/(lambda) xx100% =300%`
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