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Staements I: .zX^4 undergoes 2 alpha-dec...

Staements I: `._zX^4` undergoes `2 alpha`-decays, `2 beta`-decays (negative `beta`) and `2 gamma`-decays. As a result, the daughter product is `._z._-2X^(A-B)`.
Staements II: In `alpha`-decay, the mass number decreases by 4 unit and atomic number decreases by `2` unit. In `beta`-decay (negative `beta`), the mass number remains unchanged and atomic number increases by `1` unit. In `gamma`-decay, mass number and atomic number remain unchanged.

A

Statement-1 is true, Statement-2: is true, Statement-2 is a correct explanation for Statement-1.

B

Statement-1 is true, Statement-2: is true, Statement-2 is NOT a correct explanation for Statement-1.

C

Statement-1 is true but statement-2 is false

D

Statement-1 is false, Statement-2 is true

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The correct Answer is:
A
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Staements I: ._zX^4 undergoes 2 alpha -decays, 2 beta -decays (negative beta ) and 2 gamma -decays. As a result, the daughter product is ._z-2X^(A-B) . Staements II: In beta -decay, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In beta -decay (negative beta ), the mass number remains unchanged and atomic number increases by 1 unit. In gamma -decay, mass number and atomic number remain unchanged.

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In which of the following decays the atomic number decreases?

Assertion : After emission of one alpha -particle and two beta -particles, atomic number remains unchanged. Reason : Mass number changes by four.

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