Two masses `m_1` and `m_2` are attached to the ends of a massless string which passes over a frictionless pulley attached to the top of an inclined plane. The angle of inclination of the plane is `theta`. Take `g=10ms^(-2)`

if `m_(1)=10 kg,m_(2)=5 kg , theta=30^(@)`, what is the acceleration of mass `m_(2)`?

Options

A. zero
B. `(2//3)ms^(-2)`
C. `5 ms^(-2)`
D. `10//3 ms^(-2)`

Answer

A

Explanation

`a=((m_(2)-m_(1) sin alpha)g)/((m_(1)+m_(2)))=((5-10 sin 30^(@))g)/((m_(1)+m_(2)))=0`