Two liquids at temperature 60^@ C and 20...

Two liquids at temperature `60^@ C` and `20^@ C` respectively have masses in the ratio `3:4` their specific heat in the ratio `4:5`. If the two liquids are mixed, the resultant temperature is.

`70^(@)C`

`50^(@)C`

`40^(@)C`

`35^(@)C`

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The correct Answer is:

`(3m) (4C)(60-T)=(4m)(5C)(T-20)rArr T=35^(@)C`

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