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The rms speed of oxygen molecules in a g...

The rms speed of oxygen molecules in a gas is `v`. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become

A

v

B

`vsqrt(2)`

C

`2v`

D

4v

Text Solution

Verified by Experts

The correct Answer is:
C
`V_(RMS)=sqrt((3RT)/(M_(0)))=v`
For oxygen `V_(rms)=sqrt((3Rxx2T)/(M_(0)//2))=2v`
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