Two wires of the same material and length but diameters in the ratio `1:2` are stretched by the same force. The potential energy per unit volume for the two wires when stretched will be of the ratio.

Options

A. `1:1`
B. `2:1`
C. `4:1`
D. `16:1`

Answer

D

Explanation

`(r_(1))/(r_(2))=1/2rArr ` PE (per unit volume) `=1/(2Y)(F/A)^(2)`
`PE prop 1//A^(2) rArr (PE_(1))/(PE_(2))=(A_(2)^(2))/(A_(1)^(2))=16:1`