A uniform rod of mass m and length L is suspended with two massless strings as shown in the figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings `T_1/T_2` is:

Options

A. `1:1`
B. `1:2`
C. `2:1`
D. `4:3`

Answer

C

Explanation

`tau_(A)=0`
`T_(1)xx(3L)/4-mg L/2=0....(1)`
`T_(1)=(2mg)/3`
`T_(1)+T_(2)=mg`....(2)
`T_(2)=(mg)/3=(T_(1))/(T_(2))=2/1`