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A parallel plate capacitor is charged to...

A parallel plate capacitor is charged to a potential difference of 100V and disconnected from the source of emf. A slab of dielectric is then inserted between the plates. Which of the following three quantities change?

A

only (i) and (ii)

B

only (i) and (iii)

C

only (ii) and (iii)

D

All (i),(ii) and (iii)

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The correct Answer is:
A
The charge of the plates cannot change because the plates are isolated. Inserting the dielectric changes the capacitance and therefore changes the potential difference (from V=Q/C), since the charge is fixed.
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