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a conducting disc of radius R rotates ab...

a conducting disc of radius `R` rotates about its axis when an angular velocity `omega`.Then the potential difference between the centre of the disc and its edge is (no magnetic field is present ):

A

zero

B

`(m_(0)omega^(2) R^(2))/(2e)`

C

`(m_(0)omegaR^(3))/(3e)`

D

`(em_(0)omegaR^(2))/2`

Text Solution

Verified by Experts

The correct Answer is:
B
`eE=m_(0)omega^(2)r `
`rArr intEdr=(m_(0)omega^(2))/e int_(0)^(R) dr`
`rArr V=(m_(0)omega^(2) R^(2))/(2e)`
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