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The length of two metallic rods at tempe...

The length of two metallic rods at temperatures `theta` are `L_(A)` and `L_(B)` and their linear coefficient of expansion are `alpha_(A)` and `alpha_(B)` respectively. If the difference in their lengths is to remian constant at any temperature then

A

`L_(A)//L_(B)=alpha_(A)//alpha_(B)`

B

`L_(A)//L_(B)=alpha_(B)//alpha_(A)`

C

`alpha_(A)=alpha_(B)`

D

`alpha_(A)alpha_(B)=1`

Text Solution

Verified by Experts

The correct Answer is:
B
Change in `L_(A)`=change in `L_(B)`
i.e. `DeltaL_(A)=DeltaL_(B)`
`rArr alpha_(A) DeltaTL_(A)=alpha_(B)DeltaTL_(B)`
or `alpha_(A) L_(A)=alpha_(B) L_(B)`
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