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As the distance between the plates of a ...

As the distance between the plates of a parallel plate capacitor decreased

A

chances of electrical break down will increases if potential difference between the plates is kept constant.

B

chance of electrical break down will decreases if potential difference between the plates is kept constant.

C

chance of electric break down will increases if charge on the plates is kept constant

D

chance of electrical break down will decrease if charge on the plate is kept constant.

Text Solution

Verified by Experts

The correct Answer is:
A

When charge on plate is constant electric field remains constant`E=Q/(2Aepsilon_(0))`
In case when potential difference is constant E=V/d
Electric field increases when 'd' decreases and hence chances of breakdown increases.
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