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Statement-1:A nucleus having energy E(1)...

Statement-1:A nucleus having energy `E_(1)` decays by `beta^(-)` emission to daugther nucleus having energy `E_(2)`, but the `beta^(-)` rays are emitted with a continuous energy spectrum having end point energy `(E_(1)-E_(2))`.
Statement-2: To conserve energy and momentum in `beta`-decay, at least three particles must take part in the transformation.

A

Statement-1 is correct but statement-2 is not correct

B

Statement-1 and statement-2 both are correct and statement-2 is the correct explanation of statement-1

C

Statement-1 is correct, statement is-2 is correct and statement -2 is not the correct explanation of statement-1

D

Statement-1 is incorrect, statement-2 is correct

Text Solution

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The correct Answer is:
B

Statement-1: Energy of `beta`-particle from `0` to maximum so `E_(1)-E_(2)` is the continuous energy spectrum.
Statement-2: For energy conservation and momentum at least three particles daughter nucleus `+beta^(-1)` and antineutron.
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RESONANCE-NUCLEAR PHYSICS-Exercise-3 Part-II JEE (MAIN)
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  9. In gamma ray emission from a nucleus

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  11. This question contains Statement - 1 and Statement -2 Of the four choi...

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  12. The above is a plate of binding energy per nucleon E(0) against the nu...

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