Calculate the amount of energy released during the `alpha`-decay of
`._(92)^(238)Urarr_(90)^(234)Th+._(2)^(4)He`
Given: atomic mass of `._(92)^(238)U=238.05079 u`, atomic mass of `._(90)^(234)Th=234.04363 u`,
atomic mass `._(2)^(4)He=4.00260u , 1u=931.5 MeV//c^(2)`. Is this decay spontaneous?Give reason.

Explanation

To calculate the energy released during the alpha decay of Uranium-238 to Thorium-234 and an alpha particle, we will follow these steps:

### Step 1: Write down the equation for the alpha decay
The equation for the alpha decay is:
\[ _{92}^{238}U \rightarrow _{90}^{234}Th + _{2}^{4}He \]

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