A neutron is absorbed by a `._(3)^(6)Li` nucleus with the subsequent emission of an alpha particle.
(i) Write the corresponding nuclear reaction.
(ii) Calculate the energy released, in `MeV`, in this reaction.
[Given: mass `._(3)^(6)Li=6.015126u`, mass (neutron)`=1.0086654 u` mass (alpha particle) `=0.0026044 u` and mass (triton) `=3.010000 u`. Take `i u=931 MeV//c^(2)`]

Explanation

To solve the problem step by step, we will address both parts of the question: writing the nuclear reaction and calculating the energy released.

### Step 1: Write the corresponding nuclear reaction

The reaction involves a lithium-6 nucleus absorbing a neutron and emitting an alpha particle.

1. The lithium-6 nucleus is represented as \( _{3}^{6}\text{Li} \).
2. A neutron is represented as \( n \).
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